1/2x^4-8x^2=0

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Solution for 1/2x^4-8x^2=0 equation: 


x in (-oo:+oo)

(1/2)*x^4-(8*x^2) = 0

(1/2)*x^4-8*x^2 = 0

1/2*x^4-8*x^2 = 0

t_1 = x^2

1/2*t_1^2-8*t_1^1 = 0

1/2*t_1^2-8*t_1 = 0

DELTA = (-8)^2-(0*1/2*4)

DELTA = 64

DELTA > 0

t_1 = (64^(1/2)+8)/(1/2*2) or t_1 = (8-64^(1/2))/(1/2*2)

t_1 = 16 or t_1 = 0

t_1 = 0

x^2+0 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

t_1 = 16

x^2-16 = 0

1*x^2 = 16 // : 1

x^2 = 16

x^2 = 16 // ^ 1/2

abs(x) = 4

x = 4 or x = -4

x in { 0, 4, -4 }

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